2h^2-15h+13=0

Solution for 2h^2-15h+13=0 equation:

2h^2-15h+13=0

a = 2; b = -15; c = +13;
Δ = b2-4ac
Δ = -152-4·2·13
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-11}{2*2}=\frac{4}{4}
=1
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+11}{2*2}=\frac{26}{4}
=6+1/2
$